Question

If the number 6a34b4 is divisible by 3. How many values of a + b are possible?

• A. 3
• B. 1
• C. 4
• D. 2

Answer 1

The correct option is A

3

Here, 6 + a + 3 + 4 + b + 4 = 17 + a + b

Now, a + b cannot be more than 9.

Thus, only a + b = 1, 4, 7 satisfy the divisibility by 3.