If the number of electrons present in 1990 mg of perchlorate ion is a - 1023 then the value of -a - would be- Give your answer upto two decimal only- Given N A -6-02 - 1023- molar mass of Cl -35-5 g

Molar mass of ClO_4^ = 35.5 + 16 × 4 g = 99.5 g Number of moles = 1990 × 10^ 399.5 = 20 × 10^ 3 number of electrons in ...

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Stoichiometric Calculations

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If the number of electrons present in $1990 m g$ of perchlorate ion is $a \times 10^{23}$ then the value of $‘ a^{'}$ would be? Give your answer upto two decimal only.
(Given $N_{A} = 6.02 \times 10^{23}$ , molar mass of $C l = 35.5 g$ )

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