If the number of five digit numbers with distinct digits and $2$ at the $10 th$ place is $336 k$ , then $k$ is equal to :

8

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7

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4

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Solution

The correct option is A $8$
Total numbers that can be formed are
$= 8 \times 8 \times 7 \times 6 = 8 \times 336 ∴ k = 8$

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If the number of five digit numbers with distinct digits and 2 at the 10th place is 336k, then k is equal to :

The correct option is A 8Total numbers that can be formed are =8×8×7×6=8×336∴k=8

If the number of five digit numbers with distinct digits and $2$ at the $10 th$ place is $336 k$ , then $k$ is equal to :

The correct option is A $8$
Total numbers that can be formed are
$= 8 \times 8 \times 7 \times 6 = 8 \times 336 ∴ k = 8$