Question

If the number of five digits with distinct digits and $2$ at the ${10}^{th}$ place is $336k,$ then $k$ is equal to:

• A. $8$
• B. $7$
• C. $4$
• D. $6$

Answer 1

The correct option is A

$8$

Explanation for correct option:

Given that,

1. Five digit number
2. $2$ at the ${10}^{th}$ place

So $0$ and $2$ cannot be in the ten thousand place. So the number possible digit is $8$

Similarly in the thousand place $2$ and the digit in the ten thousand place is not possible.

So the no of possible digits is $8$

Similarly in the hundred place number of possible digit is $7$

The number of possible digit in unit place is $6$

So the total number that can be formed are $=8\times 8\times 7\times 6$

$=8\times 336$

Therefore $k=8$

Hence, option (A) $8$, is the correct answer.