Question

If the number of moles of adenine in DNA of E.coli sample is 4,65,000, the number of moles of guanine present in its DNA is:

[Given: $\frac{A+T}{G+C}=0.93$]

• A. 5,00,000
• B. 4,65,000
• C. 3,65,000
• D. 9,30,000

Answer 1

The correct option is A 5,00,000

The number of moles of thymine should be equal to those of adenine.

Number of moles of adenine = $4,65,000$ = Number of moles of thymine

Hence,

$A+T=9,30,000$

Since,

$\frac{A+T}{G+C}=0.93$

$(G+C)=1,000,000$.

Number of moles of guanine = Number of moles of cytosine

Therefore, the number of moles of guanine should be $\frac{1,000,000}{2}=5,00,000$

Hence, option $A$ is correct.