If the number of students playing each game in school S is increased by $15 %$ and the number of students playing each game in school Q is decreased by $5 %$ , what will be the difference between the number of students in school S and Q?

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218

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356

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224

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205

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Solution

The correct option is E 205
$= (\frac{260 \times 115}{100} + \frac{320 \times 115}{100} + \frac{160 \times 115}{100}) - (\frac{240 \times 95}{100} + \frac{180 \times 95}{100} + \frac{260 \times 95}{100})$
$= (2.60 \times 11.5 + 320 \times 115) - (2.40 \times 95 + 180 \times 95 + 2.60 \times 95)$
$= (299 + 368 + 184) - (228 + 171 + 247)$
$= 851 - 646 = 205$

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If the number of students playing each game in school S is increased by 15% and the number of students playing each game in school Q is decreased by 5%, what will be the difference between the number of students in school S and Q?

The correct option is E 205=(260×115100+320×115100+160×115100)−(240×95100+180×95100+260×95100) =(2.60×11.5+320×115)−(2.40×95+180×95+2.60×95) =(299+368+184)−(228+171+247) =851−646=205

If the number of students playing each game in school S is increased by $15 %$ and the number of students playing each game in school Q is decreased by $5 %$ , what will be the difference between the number of students in school S and Q?