If the number of terms in the expansion of 1-2-x-4-x2n- x-0- is 28 - then the sum of the coefficients of all the terms in this expansion-is-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Multinomial Expansion

If the number...

Question

If the number of terms in the expansion of ${(1 - \frac{2}{x} + \frac{4}{x^{2}})}^{n}$ , $x \neq 0$ , is $28$ , then the sum of the coefficients of all the terms in this expansion,is:

243

No worries! We‘ve got your back. Try BYJU‘S free classes today!

729

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2187

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 729
$total number of terms =^{n + 2} C_{2} = 28 (n + 2) (n + 1) = 56 n = 6$
Sum of coefficients $= (1 - 2 + 4)^{n} = 3^{6} = 729$

Suggest Corrections

Similar questions

Q. If the number of terms in the expansion of

{(1 - \frac{2}{x} + \frac{4}{x^{2}})}^{n}

x \neq 0

, is

28

, then the sum of the coefficients of all the terms in this expansion,is:

Q. If the number of terms in the expansion of

{(1 - \frac{2}{x} + \frac{4}{x^{2}})}^{n}, x \neq 0

, is 28, then the sum of the coefficients of all the terms in this expansions, is

Q. If the number of terms in the expansion of

{(1 - \frac{2}{x} + \frac{4}{x^{2}})}^{n}, x \neq 0

, is

28

, then the sum of coefficients of all the terms in this expansion, is:

If the number of terms in the expansion of ${(1 - \frac{2}{x} + \frac{4}{x^{2}})}^{n}$ , $x \neq 0$ is 28, then the sum of the coefficients of all the terms in this expansion, is :

Q. If the number of term in the expansion of

{(1 - \frac{2}{x} + \frac{4}{x^{2}})}^{n}, x \neq 0

28

, then the sum of the coefficients of all the term in this expansion, is:

Join BYJU'S Learning Program

If the number of terms in the expansion of (1−2x+4x2)n, x≠0, is 28, then the sum of the coefficients of all the terms in this expansion,is:

The correct option is B 729total number of terms =n+2C2=28(n+2)(n+1)=56n=6 Sum of coefficients =(1−2+4)n=36=729

If the number of terms in the expansion of ${(1 - \frac{2}{x} + \frac{4}{x^{2}})}^{n}$ , $x \neq 0$ , is $28$ , then the sum of the coefficients of all the terms in this expansion,is:

The correct option is B 729
$total number of terms =^{n + 2} C_{2} = 28 (n + 2) (n + 1) = 56 n = 6$
Sum of coefficients $= (1 - 2 + 4)^{n} = 3^{6} = 729$