If the number ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯27215x2 is completely divisible by 11, then the smallest whole number in place of x will be
A
3
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B
2
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C
1
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D
5
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Solution
The correct option is A3 Using "divisibility by 11 rule"
Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. Hence, 27215x2 is divisible by 11, then (2+2+5+2)−(7+1+x) is divisible by 11 (8+x) is divisible by 11 11 is divisible by 11
The smallest whole number which can be substituted in the place of x to satisfy the
above equation is 3 such that 11 is divisible by 11.
Hence the answer is 3.