If the numbers 3, 5, 7, 4 have frequencies x, x+4, x-3, x+8 with their arithmetic mean of 4, then x will be _____.
53
Given:
xi3574fixx+4x−3x+8
∴∑xifi=3x+5(x+4)+7(x−3)+4(x+8)=3x+5x+20+7x−21+4x+32=19x+31 …(i)
and ∑fi=x+x+4+x−3+x+8=4x+9 …(ii)
Given ∑fixi∑fi=4⇒19x+314x+9=4
[From Eqs.(i) and (ii)]
⇒19x+31=16x+36⇒3x=5∴ x=53