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Question

If the numbers a,b,c are in A.P then the value of a−5b+4c equals to

A
c+b2a
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B
0
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C
3b
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D
3b
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Solution

The correct option is A c+b2a
If a,b,c are in A.P, lets assume the common difference is d.
Therefore b=a+d,c=a+2d.
Then a5b+4c can be written as a5(a+d)+4(a+2d)
=a5a5d+4a+8d
=3d
=2a2a+3d
=(a+d)+(a+2d)2a
=c+b2a

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