If the numbers a,b,c are in A.P then the value of a−5b+4c equals to
A
c+b−2a
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B
0
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C
−3b
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D
3b
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Solution
The correct option is Ac+b−2a If a,b,c are in A.P, lets assume the common difference is d. Therefore b=a+d,c=a+2d. Then a−5b+4c can be written as a−5(a+d)+4(a+2d) =a−5a−5d+4a+8d =3d =2a−2a+3d =(a+d)+(a+2d)−2a =c+b−2a