Question

If the numbers $\frac{8}{10}$, $\frac{81}{100}$ and $\frac{8}{100}$ are arranged from smallest to largest, the correct order is:

• A. $\frac{8}{10}<\frac{81}{100}<\frac{8}{100}$
• B. $\frac{81}{100}<\frac{8}{10}<\frac{8}{100}$
• C. $\frac{8}{100}<\frac{8}{10}<\frac{81}{100}$
• D. $\frac{8}{100}<\frac{8}{10}<\frac{81}{100}$

Answer 1

Answer: (D)

$\frac{8}{100}<\frac{8}{10}<\frac{81}{100}$

Fractions $\frac{81}{100}$ and $\frac{8}{100}$ have the same denominator so, we will convert the fraction $\frac{8}{10}$ with denominator $100.$

$\begin{array}{cc}\frac{8}{10}& =\frac{8}{10}\times \frac{10}{10}\\ & =\frac{80}{100}\end{array}$

Now, we can arrange the fractions by just comparing the numerator of the fractions,

$\begin{array}{c}\frac{8}{100}<\frac{80}{100}<\frac{81}{100}\\ \Rightarrow \frac{8}{100}<\frac{8}{10}<\frac{81}{100}\end{array}$