If the numbers from 1 to 45 which are exactly divisible by 3 are arranged in ascending order, minimum number being on the top, which would come at the ninth place from the top ?
A
18
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B
21
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C
24
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D
27
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Solution
The correct option is D27 Numbers from 1 to 45 which are exactly divisible by 3 are arranged in ascending order; 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45
If the minimum number i.e., 3 is considered to be at the top, the ninth number from the top is 27. Thus 27 or Option D is correct answer.