Question

If the numbers which are divisible by $3$ from $1$ to $61$ are arranged in a descending order, then which numbers will be at $5^{th}$ place and at ${15}^{th}$ place from above?

• A. $45,18$
• B. $48,18$
• C. $48,21$
• D. $45,15$

Answer 1

The correct option is B $48,18$

Multiples of $3$ in between $1$ and $61$ are

$3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60$

Decreasing order:

$60,57,54,51,48,45,42,39,36,33,30,27,24,21,18,15,12,9,6,3$

Numbers at $5^{th}$ and ${15}^{th}$ are $48$ and $18$ respectively.

Hence, option B.