Question

If the numbers $x,6\&9$are in continued proportion, find the value of $x.$

Answer 1

The numbers $x,6\&9$are in continued proportion.

$$\begin{gathered} \therefore b^2=ac\left[a=x,b=6,c=9\right] \\ {6}^2=x\times 9 \\ \Rightarrow x=\frac{36}{9} \\ \therefore x=4 \end{gathered}$$

Hence, the value of $x$ is $4.$