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Question

If the numerator of a certain fraction is increased by 2 and the denominator increased by 1, then the resulting fraction equals 12. If however the numerator is increased by 1 and the denominator decreased by 2, then the resulting fraction equal 35 Find the fraction.

A
27
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B
67
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C
17
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D
37
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Solution

The correct option is D 27
Let the given fraction be xy
    Then, by the second condition,
    x+2y+1=12
    y=2x+3 ....... (i)
    By the second condition,
    x+1y2=35
    5x3y=11
    5x3×(2x+3)=11 ........ From (i)
    5x6x=11+9
    x=2
    Putting x=2 in (i), we get
    y=2×2+3=7
    xy=27

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