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Question

If the numerator of a fraction is increased by 20% and the denominator is decreased by 10%, then the value of the fraction is 1621. What is the original fraction?

A
35
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B
310
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C
45
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D
47
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Solution

The correct option is C 47
Let the fraction be xy.
Then from the given condition, x+20y10=1621
x+x5yy10=1621

6x59y10=1621

xy=1621×910×56=47

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