If the numerator of a fraction is increased by 25% and the denominator is doubled the resultant fraction thus obtained is 1532 What is the original fraction? (Andhra bank SO)
A
34
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B
45
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C
58
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D
12
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Solution
The correct option is A34 Let the actual fraction be = nm Then, 1.25n2m= 5n8m=1532 ⇒nm = 15×832×5 = 34