If the obtuse angle bisector and angular bisector contains origin is same for the pair of lines 2x+3y−λ=0 and 3x+2y−(λ+2)=0 then λ belongs to
A
(−2,0)
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B
(−∞,−2)∪(0,∞)
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C
(−∞,−2]∪[0,∞)
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D
None of the above
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Solution
The correct option is B(−∞,−2)∪(0,∞) a1x+b1y+c1=2x+3y−λ=0 a2x+b2y+c2=3x+2y−(λ+2)=0
here a1a2+b1b2>0 ⇒obtuse angle bisector is L1√a21+b21=+L2√a22+b22
Now at origin L1L2=(−λ)(−(λ+2))>0 ⇒λ(λ+2)>0 ⇒λ∈(−∞,−2)∪(0,∞)