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Question

If the obtuse angle bisector and angular bisector contains origin is same for the pair of lines 2x+3yλ=0 and 3x+2y(λ+2)=0 then λ belongs to

A
(2,0)
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B
(,2)(0,)
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C
(,2][0,)
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D
None of the above
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Solution

The correct option is B (,2)(0,)
a1x+b1y+c1=2x+3yλ=0
a2x+b2y+c2=3x+2y(λ+2)=0
here a1a2+b1b2>0
obtuse angle bisector is L1a21+b21=+L2a22+b22
Now at origin
L1L2=(λ)((λ+2))>0
λ(λ+2)>0
λ(,2)(0,)

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