Question

If the odds in favour of an event be $3:5$, then the probability of non-occurrence of the event is

• A. $\frac{3}{5}$
• B. $\frac{5}{3}$
• C. $\frac{3}{8}$
• D. $\frac{5}{8}$

Answer 1

The correct option is D

$\frac{5}{8}$

Explanation for correct option:

From the classical definition of probability we know that

Probability of an event $=\frac{\mathrm{number}\mathrm{of}\mathrm{favorable}\mathrm{outcomes}}{\mathrm{total}\mathrm{number}\mathrm{of}\mathrm{outcomes}}$

Given that the odds of an event be $3:5$

Total number of cases$=5+3=8$

Total number of favourable cases $=3$

So the probability of its occurrence is $=\frac{3}{8}$

Therefore the probability of of its non-occurrence is $=1-\frac{3}{8}=\frac{5}{8}$

Hence, option (D) $\frac{5}{8}$ is correct answer.