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Question

If the ordered pairs(x1,y1) and (x2,y2) satisfying the system of equations log10(y)-log10|x| = log100(4) and log100| x + y |=1/2 find value of x1x2y1y2

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Solution

Dear Student, log10y-log10x= log1004log10yx= log1024=12log104= log104yx= 2 y = 2x or y = -2x.....1Again log100x+y= 1/2 x+y= 10x+y=10........2 Neglecting x+y=-10 because log cannot take negative valueNow solnving y = 2x and x+y=10 3x=10 x = 103Now basically this is x1 = 103 So y =203 and this is y1Now solnving y = -2x and x+y=10 -x=-10 x = 10Now basically this is x2 =10 .So y = -20 and this is y2So x1× x2× y1×y2=103×203×10×-20=-400009
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