Question

If the origin is the centroid of a triangle ABC having vertices A(a, 1, 3),

B(-2, b -5) and C(4, 7, C), find the values of a, b, c.

Answer 1

We have A(a, 1, 3), B(-2, b -5) and C(4, 7, C)

Now,

$\frac{a-2+4}{3}=0,\frac{1+b+7}{3}=0$ and $\frac{3-5+c}{3}=0,$

$\therefore$ a =-2, b = -8 and c = 2