Given vertices are A(2,0),B(2,3) and C(0,3)
Now, the side lengths are
AB=√02+32=3 units
BC=√22+0=2 units
AC=√22+32=√13 units
By observation, we see that
AC2=AB2+BC2
Given triangle is right-angled at vertex B
So, the orthocentre is (α,β)=(2,3)
∴α+β=2+3=5