If the osmotic pressure of 5 g per litre solution of a compound at $27^{o} C$ is 0.025 atm, calculate the molecular mass of the compound.

4826 g

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1926 g

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426 g

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4926 g

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Solution

The correct option is C 4926 g
we have,
$π = C R T$
$0.025 a t m = \frac{g i v e n w e i g h t}{m o l e c u l a r w e i g h t * v o l u m e} * 0.082 * 300$

$0.025 a t m = \frac{5}{m o l e c u l a r w e i g h t * 1} * 0.082 * 300$

molecular weight = 4926 g

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