Question

If the overbridge is concave instead of convex, the thrust on the road at lowest point of the overbridge would be

• A. $mg-\frac{m{v}^2}{r}$
• B. $mg+\frac{m{v}^2}{r}$
• C. $\frac{m{v}^2}{r}$
• D. $mg$

Answer 1

The correct option is B $mg+\frac{m{v}^2}{r}$

As the centripetal force is $\frac{m{v}^2}{R}$ and its direction is outwards the circle (radial direction).
In our case, as there is concave road hence this direction of centripetal is downwards and therefore total force on ground is (gravitational force + centripetal force) $\frac{m{v}^2}{R}+mg$.