If the P.E of a system decreases by 40 J while the K.E remains constant, then the work done by external agent will be.

40 J

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-40 J

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20 J

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0 J

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Solution

The correct option is B -40 J
If the final Potential energy of a system is lesser than its initial potential energy, then the internal conservative force must have done some positive work. To keep the K.E constant, the work done by external agent has to be negative.

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Under a constant Electric field of 5 N/C, a positive charge is moved against the field by an external agent such that the P.E of the system is increased by 10 J. Does this imply that the work done by external agent is +10 J?

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If the P.E of a system decreases by 40 J while the K.E remains constant, then the work done by external agent will be.

The correct option is B -40 JIf the final Potential energy of a system is lesser than its initial potential energy, then the internal conservative force must have done some positive work. To keep the K.E constant, the work done by external agent has to be negative.

The correct option is B -40 J
If the final Potential energy of a system is lesser than its initial potential energy, then the internal conservative force must have done some positive work. To keep the K.E constant, the work done by external agent has to be negative.