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Question

If the pth term of an AP is q and the qth term is p, then nth term of the A.P is:

A
p+qn
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B
pqn
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C
p+q
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D
pn
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Solution

The correct option is A p+qn
ap=a+(p1)d=q...(1)aq=a+(q1)d=p...(2)

(2)(1)pq=d[(q1)(p1)]
=d(qp)

d=pqqp=1

Substituting the value of p in (1)a=p+q1

Substitute the values of a and d in
an=a+(n1)d
an=p+q1+(n1)1
an=p+qn

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