Question

If the pair of integers whose sum is zero but difference is $12$ are $xandy$. Then $xy=-m$.Find $m$

Answer 1

$x+y=0⟶\left(i\right)$

$x-y=12⟶\left(ii\right)$

Adding ${eq}^n\left(i\right)\&\left(ii\right)$, we have

$x+y+x-y=0+12$

$\Rightarrow 2x=12$

$\Rightarrow x=6$

Substituting the value of x in ${eq}^n\left(i\right)$, we have

$6+y=0$

$\Rightarrow y=-6$

$\therefore xy=6\times (-6)=-36⟶\left(iii\right)$

$xy=-m⟶\left(iv\right)\left\{Given\right\}$

From ${eq}^n\left(i\right)\&\left(ii\right)$, we get

$m=36$