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Question

If the pair of linear equations
3x+2y=1
(2k+1)x+(k+2)y=k−1
Has infinitely many solution, then the value of k is

A
2
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B
4
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C
3
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D
5
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Solution

The correct option is A 2
For infinitely many solutions,
32k+1=2k+2=1k1

Thus,
2(k1)=k+2
2k2=k+2
k=4

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