If the pair of linear equations $x + 2 y - 4 = 0$ and $2 x + 4 y - 12 = 0$ are plotted graphically, How many solution(s) do we get.

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Solution

Equation 1:
x + 2y - 4 = 0
x + 2y = 4

x y

0 2

4 0

Equation 2:
2x + 4y = 12

x y

0 3

6 0

Plotting the linear equation graphically:

This shows that both the linear equations are parralel to each other. Thus, there is no solution for x and y.

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If the pair of linear equations x+2y−4=0 and 2x+4y−12=0 are plotted graphically, How many solution(s) do we get.

Equation 1: x + 2y - 4 = 0 x + 2y = 4 x y 0 2 4 0 Equation 2: 2x + 4y = 12 x y 0 3 6 0 Plotting the linear equation graphically: This shows that both the linear equations are parralel to each other. Thus, there is no solution for x and y.

If the pair of linear equations $x + 2 y - 4 = 0$ and $2 x + 4 y - 12 = 0$ are plotted graphically, How many solution(s) do we get.

Equation 1:
x + 2y - 4 = 0
x + 2y = 4

x y

0 2

4 0

Equation 2:
2x + 4y = 12

x y

0 3

6 0

Plotting the linear equation graphically:

This shows that both the linear equations are parralel to each other. Thus, there is no solution for x and y.