If the pair of linear equations x – y = 1, x + ky = 5 has a unique solution x = 2, y = 1, then value of k is
2
3
-3
4
Substitute the value of x and y in the equation x + ky = 5
put x = 2, y = 1
⇒ 2 + k(1) = 5
⇒ k = 5 - 2
⇒ k = 3
we get,k = 3
A pair of linear equations which has a unique solution x=−2,y=1 is
Find the value for k which each of the following systems of equations has a unique solution:
5x−7y−5=0,2x+ky−1=0.