If the pair of lines ax2+2hxy+by2+2gx+2fy+c=0 intersect on the y -axis , then
Solution: ax2+by2+2gx+2fy+2hxy+c=0 above equation represents pair of straight lines if abc+2fgh−af2−bg2−ch2=0
∴
pair of lines intersect on y axis x=0
by2+2fy+c=0
it is a quadratic in 'y'. so to get point of intersection on y axis we need two equal and real roots of this quadratic
∴D=0
⇒4f2−4bc=0
⇒f2=bc
put this value in equation
abc+2fgh−abc−bg2−ch2=0
⇒2fgh=bg2+ch2
Answer : option (A)