Question

If the parallel sides of trapezium measure 3 cm and 4 cm, and the height of the trapezium is 6 cm, then find its area.

• A. 12 cm²
• B. 18 cm²
• C. 21 cm²
• D. 42 cm²

Answer 1

The correct option is C 21 cm²

Area of a trapezium of height $h$ and parallel sides $a$ and $b$ is given by
$\text{area}=\frac{1}{2}h(a+b).$
$\therefore \text{Area}=\frac{1}{2}6(3+4)=21{\text{cm}}^2$