Question

If the particles listed below all have the same kinetic energy, which one would posses the shortest de-Broglie wavelength.

• A. Electron
• B. $\alpha -$particle
• C. Proton
• D. All of the above

Answer 1

The correct option is A Electron

As per the formula,

$\lambda =\frac{h}{p}$

Since $\lambda =\frac{h}{mv}$

thus, $\lambda \propto \frac{1}{\sqrt{m}}$

Wavelength and mass has inverse dependence.

Since, mass of electron is the least out of all the three particles $\therefore$, electron has the largest de-Broglie wavelength.