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Nitrogen

If the percen...

Question

If the percentage of nitrogen in an organic compound is $12.5 %$ , then how much of the organic compound should be taken? so as to produce $50 m l$ of $N_{2}$ at $300 K$ and $715 m m$ pressure.
[Aq. tension $= 15 m m$ ]

0.419 g

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0.0149 g

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0.914 g

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0.941 g

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Solution

The correct option is D $0.419 g$
$P_{1} = 715 m m$
$V_{1} = 50 m l$
$T_{1} = 300 k$

at STP

$P_{2} = 760 m m$
$V_{2} = ?$
$T_{2} = 273 k$
aq. Tension $=$ 15mm

$P_{1}^{x} = 715 - 15 = 700 m m$

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

$V_{2} = \frac{P_{1} V_{1} T_{2}}{P_{2} T_{1}} = \frac{700 \times 50 \times 273}{760 \times 300}$

$V_{2} = 41.90 m l$

% $N_{2} = \frac{28}{22400} \times \frac{V_{2}}{m} \times 100$

$12.5 = \frac{28}{22400} \times \frac{41.9}{m} \times 100$

$m = 0.419 g$
Hence, the correct option is $A$

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