Question

If the percentage yield of the $1st$ step is $80\%$ and that of the $2nd$ step is $75\%$, then what is the expected overall percentage yield for producing $Ca{O}_3$ from $CaC{l}_2$?

• A. $50\%$
• B. $70\%$
• C. $55\%$
• D. $60\%$

Answer 1

The correct option is D $60\%$

${CaCl}_2\underset{}{\overset{1^{st}step}{\to }}\times \underset{}{\overset{2^{nd}step}{\to }}{CaCO}_3$

Let $100$ unit of $CaC{l}_2$ taken

amount of $\times$ produced $=80unit$

amount of $CaC{O}_3$ produced $=\frac{80\times 75}{100}=60$

Hence $\%$ yield of $CaC{O}_3$ by $CaC{l}_2=60\%$