Question

If The perimeter of a rhombus is $40cm$. If the difference in the diagonal is $4cm$, find the area of the rhombus.

Answer 1

Perimeter of rhombus $=4x=40cm$

Side$=10cm$

Length of one diagonal $=16cm$

In $△AOB,OB=\sqrt{100-64}$

$=6cm$

So, $d_1=16cm$

$d_2=6\times 2=12cm$

Area $=\frac{1}{2}\times d_1\times d_2=\frac{1}{2}\times 6\times 12=36{cm}^2$