Question

If the perimeter of a square is $(4a+8)$ unit, then its area will be?

• A. $(a^2+4a+4)$ square unit
• B. $(10a^2-a-8)$ square unit
• C. $(a+2a^2+4)$ square unit
• D. $(4a^2+4a-4)$ square unit

Answer 1

Answer: (A)

$(a^2+4a+4)$ square unit

Perimeter of a square=4*(side)

Therefore, side=perimeter/4

side$=(4\ast a+8)/4$

$=(a+2)$

Area of a Square $=sid{e}^2$

Hence, area $=(a+2{)}^2$

$=a^2+2\ast a\ast 2+2^2$

$=a^2+4a+4$

Hence A is the correct option.