If the perimeter of the rhombus is 20 cm and length of one of its diagonal is 6 cm, the length of the other diagonal is -
8 cm
Given perimeter 4a = 20
a = 5 cm
Length of one diagonal = 6 cm
Let the length of the other half diagonal be `x'
32 + x2 = 25
x = 4 cm
Length of the diagonal = 8 cm