If the perpendicular distances of two chords are equal from the centre of a circle then the length of the two chords is
A
Different
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B
Can't say
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C
Equal
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D
May be equal or not but doesn't depend on the distance from the centre.
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Solution
The correct option is C
Equal
Let the centre of the circle be O, be the radius and x be the perpendicular distance of the chords from the centre of the circle. Using Pythagoras theorem in Δ AOB AB=2√r2−x2 Using Pythagoras theorem in Δ COD CD=2√r2−x2 So the lengths of the two chords are alwaus always equal if their perpendicular distance from the centre to the chords is equal