If the petrol burnt per hour in driving a motor boat varies as the cube of its velocity when going against a current of C kmph, the most economical speed is
A
c2
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B
3c2
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C
√3c2
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D
c
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Solution
The correct option is C3c2 Let the petrol burnt per hour be 'y' units and V kmph be the velocity of the motor boat.. Since, y∝V3 ⇒y=kV3 where 'k' is proportionality constant. Velocity of boat against current = (V-C)kmph. Let S be the distance travelled by the boat in time t. Then petrol burnt =SV−C×kV3 Let f(V)=SV−C×kV3 f′(V)=2V3−3V2C(V−C)2 For maxima or minima, f′(V)=0 ⇒V=0,3C2 Clearly f′′(V)>0 for V=3C2 Hence, most economical speed is 3C2