Question

If the pH of $0.2M$ dibasic acid $\left(H_{2}A\right)$ is $1.699$, than its osmotic pressure at T K temperature will be?

• A. $0.22RT$
• B. $0.02RT$
• C. $0.4RT$
• D. $0.1RT$

Answer 1

The correct option is A $0.22RT$

Solution:

Osmotic Pressure $\pi =iCRT$

Where C=Molarity of solution

$\alpha =\frac{i-1}{m-1}$

$0.2=\frac{i-1}{1.699-1}$

$i=1.139$

$\pi =iCRT$

$=1.139\times 0.2RT$

$=0.22RT$