If the $p H$ of $N a O H$ solution is $12$ , then what is the amount in grams of $N a O H$ present in one litre of this solution?

40.0

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4.0

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0.4

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20.0

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Solution

The correct option is C $0.4$
It is given that the pH of $N a O H$ solution is $12$ .

We know, $p H + p O H = 14$

Hence, $p O H = 14 - 12 = 2$

But $p O H = - l o g [O H^{-}]$

Hence, $[O H^{-}] = 10^{- 2}$ M

Thus, $1$ L of $N a O H$ solution having $p H$ $= 12$ contains $0.01$ moles of it.

Molecular weight of $N a O H$ is $40$ g/mol.

Thus, weight of $N a O H$ present $= 0.01 \times 40 = 0.4$ g $N a O H$ in $1$ L of the solution.

Option C is correct.

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