If the piston is pushed at a speed of 5mms−1, the air comes out of the nozzle with a speed of
A
0.1ms−1
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B
1ms−1
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C
2ms−1
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D
8ms−1
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Solution
The correct option is C2ms−1 From equation of continuity: A1V1=A2V2 Subscript 1 stands for piston and 2 for nozzle respectively. We have: d1=20mm and d2=1mm Therefore, A1=π(202) and A1=π(12) Also, V1=5m/s Thus, π(202)×5=π(12)×V2 V2=2m/s