Question

If the pitch of a screw gauge is 0.5 mm and its least count is 0.01 mm. Find the number of divisions on the head scale.

• A. 50
• B. 100
• C. 200
• D. 500

Answer 1

The correct option is A 50

Pitch $P=0.5mm$

Least count $L.C.=0.01mm$

Number of divisions $N=\frac{P}{L.C.}=\frac{0.5}{0.01}=50$