If the pitch of the screw is doubled by keeping head of the scale divisions same, how does its least counts vary?

remains same

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doubled

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trippled

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guatrappled

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Solution

The correct option is B doubled
Least count $L . C . = \frac{P}{N}$
$⟹ L . C . \propto P$
So, least count of the screw gauge will get doubled if the pitch is doubled by keeping the head of the scale divisions same.

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Similar questions

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If the pitch of the screw is doubled by keeping head of the scale divisions same, how does its least counts vary?

The correct option is B doubledLeast count L.C.=PN⟹ L.C.∝ PSo, least count of the screw gauge will get doubled if the pitch is doubled by keeping the head of the scale divisions same.

The correct option is B doubled
Least count $L . C . = \frac{P}{N}$
$⟹ L . C . \propto P$
So, least count of the screw gauge will get doubled if the pitch is doubled by keeping the head of the scale divisions same.