Question

If the plane $3x-4y+5z=0$ is parallel to $\frac{2x-1}{4}=\frac{1-y}{3}=\frac{z-2}{a}$, then the value of $a$ is

• A. $\frac{6}{4}$
• B. $\frac{6}{5}$
• C. $0$
• D. $\frac{3}{4}$

Answer 1

The correct option is C $0$

If plane is parallel to given live then normal to plane is $\perp$ to given line

$\left(3\right)\left(4\right)+(-4)(+3)+\left(5\right)\left(a\right)=0$

$\Rightarrow a=0$