If the planes x− cy−bz= 0, cx −y+ az= 0 and bx+ ay−z = 0 pass through a straight line then find the value of $a^{2} + b^{2} + c^{2} + 2 a b c$

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Solution

The correct option is A 1
Equation of plane passing thorugh the line of intersection of two planes can be given as $π_{1} + λ π_{2} = 0$ is $(x - c y - b z) + λ (c x - y + a z) = 0$ and bx +ay -z=0 are indentical

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is:

The planes x-cy-bz=0, cx-y+az=0 and bx+ay-z=0 pass through a straight line, where a,b,c are non-zero constants. Then the value of $a^{2} + b^{2} + c^{2} + 2 a b c$ is

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If the planes x− cy−bz= 0, cx −y+ az= 0 and bx+ ay−z = 0 pass through a straight line then find the value of a2+b2+c2+2abc

The correct option is A 1Equation of plane passing thorugh the line of intersection of two planes can be given as π1+λπ2=0 is (x−cy−bz)+λ(cx−y+az)=0 and bx +ay -z=0 are indentical

If the planes x− cy−bz= 0, cx −y+ az= 0 and bx+ ay−z = 0 pass through a straight line then find the value of $a^{2} + b^{2} + c^{2} + 2 a b c$

The correct option is A 1
Equation of plane passing thorugh the line of intersection of two planes can be given as $π_{1} + λ π_{2} = 0$ is $(x - c y - b z) + λ (c x - y + a z) = 0$ and bx +ay -z=0 are indentical