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Question

If the planes xcybz=0, cxy+az=0 and bx+ayz=0 pass through a straight line, then find the value of a2+b2+c2+2abc.

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Solution

It they passes through a straight line
∣ ∣1cbc1aba1∣ ∣=01(1a2)+c(cab)b(ac+b)=01a2c2abcabcb2=0a2+b2+c2+2abc=1

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